In a class of 100 half the students are science majors and half are liberal art majors. A student who is a science major has a 0:9 probability of passing a given test whilst a student who is liberal art major has only a probability of 0:7. We pick 2 students at random without replacement and give them the test. What is the probability that both students pass the exam

P(both students passed the exam) = 0.61948

Step-by-step explanation:

From the given information:

P(both students passed the exam) = P(both are science students or both are art major students or one is from each group)

= P (both are science students) + P(both are art students) + P(one from each group)

where;

P (both are science students) = (50/100) (0.9) × (44/99) × (0.9) = 0.18

P(both students are art) = (50/100) (0.7) × (49/99) 0.7 = 0.1213

P(one of the student are from each group) = (50/100) (0.9) ×(50/99) (0.7) + (50/100) (0.7)× (50/99)(0.9) =0.3182

P(both students passed the exam) = 0.18 + 0.1213 + 0.3182

P(both students passed the exam) = 0.61948

x= 149. 24+7=31. 180-31=149

your welcome

you ignore the remainder, therefore the answer is y = x+2

step-by-step explanation:

you have to divide the denominator by the numerator. you can use synthetic division or long division.

[-5] .     1 .     7 .     11

x + 2 + 1/x+5