a retired statistician was interested in determining the average cost of a 200000 term life insurance policy for a he randomly sampled 65 subjects what value of alpha was used to create this confidence interval

The correct option is the second option

Step-by-step explanation:

From the question we are told that

   The average cost is  

   The sample size is  n =  65  

    The upper limit of the 95% confidence interval is  $1050.00

     The lower limit of the 95% confidence interval is $850.00

From the question we are told the confidence level is  95% , hence the level of significance is    

=>  

first one because it can't have a fraction in it

step-by-step explanation:

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb