Solve 2p^2 - 3p - 2 by factoring

(2p+1)(p−2)

It's out of B or C.

B

Step-by-step explanation:

To solve by factoring equate the expression to zero, that is

2p² - 3p - 2 = 0

Consider the factors of the product of the p² term and the constant term which sum to give the coefficient of the p- term.

product = 2 × - 2 = - 4 and sum = - 3

The factors are - 4 and + 1

Use these factors to split the p- term

2p² - 4p + 1p - 2 = 0 ( factor the first/second and third/fourth terms )

2p(p - 2) + 1(p - 2) = 0 ← factor out (p - 2) from each term

(p - 2)(2p + 1) = 0

Equate each factor to zero and solve for x

p - 2 = 0 ⇒ p = 2

2p + 1 = 0 ⇒ 2p = - 1 ⇒ p = -

lo98765432wqasdfghjkloi87654567890

step-by-step explanation: