4. Given: FH bisects ZEHG, ZFEHZFGH Prove: AFEH 2 AFGH
H
Reasons
Statements
1.
2.
1. FH bisects LEHG
2. LFEH F LFGH
LFHE Ź CFHG
3.
3.
4.
4.
5.
5.
AFEH AFGH
nderstandina
S
5. Glven: ZRPQ = ZRTS, R is the midpoint of Q5
Prove: APOR - ATSR

just find the gcf and solve the gcf's until you get each answer i have a really good feeling somethings missing xd (like the dimensions of the fence) *cough *cough *hint *hint

step-by-step explanation:

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

8 2/3 is the answer

step-by-step explanation: just use a calculator