A can of tuna fish has a diameter 11.4 cm and height 3.7 cm. Cans are packed snugly for shipping in boxes containing 4 layers of 5 rows by 7. How much empty space does each box contain?

14447 cm³

Step-by-step explanation:

Given that:

Diameter = 11.4cm

Height = 3.7cm

boxes has 4 layers ; 5 rows by 7

Hence, dimension of shipping boxes :

Height = height of can * layer = 3.7 * 4 = 14.8 cm

Length = 5 * diameter of can = 5 * 11.4 = 57cm

Width = 7 * diameter of can = 7 * 11.4 = 79.8 cm

Volume of shipping boxes :

Height * Length * Width

14.8 * 57 * 79.8 = 67319.28 cm³

For fish can:

Radius = diameter / 2 = 11. 4 / 2 = 5.7cm

Volume (V) of can = pi*radius^2*height

V = π * 5.7^2 * 3.7 = 377.66027 cm³

Total volume of cans = number of cans * V

Total volume of cans = (4 * 5 * 7 * 377.66027)

Total volume of cans = 52872.4378 cm³

Empty space = difference in volume

= 67319.28 - 52872.4378

= 14446.8422

= 14447 cm³ (approx)

i only know the sequence of arithmetic it adds the first is 5+4 then it goes up as it adds to then it is 9+5 then 14+6 then to 20+7 and so on. 5,9,14,20,27,35.

step-by-step explanation:

answer: y = -2.5x - 15

              (-6,0)

step-by-step explanation: