(algebra ii) solve the equation. check for extraneous solutions.
9|9 – 8x|= 2x + 3

9|9-8x|=2x+3 

As there is mod, there would be two solutions, one for +ve value and other for -ve valueIt will lead into either
 
1) 9(9-8x)=2x+3   OR
 2) 9(9-8x)=-(2x+3)
Now,
1)9(9-8x)=2x+3
81-72x=2x+3
74x=78
x=39/37

2)9(9-8x)=-(2x+3)
81-72x=-2x-3
70x=84
x=6/5 

So, x would be either 39/37 or 6/5