Help plz i’ll give extra points

Given f(x) = 10x + 4 and g(x) = 3x - 8, what is f(x) + g(x) ? - 7x - 4 - 13x + 4 - 7x + 4 - 13x - 4

Suppose that f(0) = −3 and f '(x) ≤ 8 for all values of x. how large can f(4) possibly be? solution we are given that f is differentiable (and therefore continuous) everywhere. in particular, we can apply the mean value theorem on the interval [0, 4] . there exists a number c such that

This is so harddd! solve. 1 + 1 = solve 4 + 4 = solve 3 x 3