A ball is thrown from the top row of seats in a stadium. The function h(t) = - 16t^2 + 80t + 96 gives the height, in feet, of the ball t seconds after it is thrown. How long will it be before the ball hits the ground?

2s or 3s

Step-by-step explanation:

Given the function that models the height of the object as;

h(t) = - 16t^2 + 80t + 96

The ball reaches the ground when h = 0

Substitute

0 = - 16t^2 + 80t + 96

Divide through by -16

0 = t²-5t-6

t²-5t-6 = 0

t²-2t-3t+6 = 0

t(t-2)-3(t-2) = 0

(tt-2)(t-3) = 0

t - 2 = 0 and t-3 = 0

t = 2 and 3s

Hence it will take the ball 2s or 3s to reach the ground

none of the above.

for one of the equations to be used in the process, there has to be a term in the equation since squared is .

since there is only a term in the first equation, we cannot derive a from completing the square.

solving with completing the square

damm bro the struggle

step-by-step explanation: