Find the inverse function of f(x)=15x-1

f'(x) = (x + 1)/15

Step-by-step explanation:

f(x) = 15x -1,

Think of the term "f(x)" as a single variable, then solve for the term "x", manipulate the equation like how one would manipulate a literal equation, by inverse operations.

f(x) = 15x - 1

+1            +1

f(x) + 1 = 15x

/15         /15

(f(x) + 1)/15 = x

This means that (denote in the way one would denote an inverse of a function);

f'(x) = (x + 1)/15

its 4 because 2 times 2 is 4, if you double the number two you get four

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3