Use the remainder theorem to determine if x = 2 is a zero of the following polynomial, and find the quotient and the remainder. p(x) = x3 + 24x2 + 108x - 320

(A) Yes, x = 2 is a zero of the polynomial.

The quotient is x² + 26x + 160 and the remainder is 0

Step-by-step explanation:

Given;

p(x) = x³ + 24x² + 108x - 320

Using remainder theorem to test if x = 2 is a zero of the given function

p(2) = (2)³ + 24(2)² + 108(2) - 320

       = 8 + 96 + 216 - 320

        = 0

Thus, x = 2 is zero of the function

(ii) to get the quotient and the remainder of the given function, divide the function by 'x - 2'

                     x² + 26x + 160

     x - 2    √ x³ + 24x² + 108x - 320

                 -  (x³ -  2x²)                      

                     0   + 26x² + 108x - 320

                          - (26x²  - 52x)                  

                               0      + 160x - 320

                                        -  (160x - 320)        

                                              0     +   0  

The quotient is x² + 26x + 160

The remainder is 0                      

Thus, the correct option is A.

Yes, x = 2 is a zero of the polynomial.

The quotient is x² + 26x + 160 and the remainder is 0            

518,400

step-by-step explanation:

the area is multiplying all the given measurements together.

40 * 18 * 30 * 24 = 518,400