Find an equation of the line that is perpendicular to the line y=5x+6 and passes through the point (-2,5) workings pls

Step-by-step explanation:

Since the equation of the line is perpendicular to the line y = 5x +6

we can use the formula:

where m1 is the slope of the line we have and,

m2 is the slope of the line we need

so here m1 is 5 as we compare it with the slope-intercept form our slope is:

our m1 is 5 but we need m2 so plugging in the value we get m2 to be:

and now we have our m2, now furthermore since the line passes through the point (-2 , 5) it means the point must lie on the line and satisfy it. We can use this point and the slope m2 and find out the equation by the point-slope form equation:

8y^50

step-by-step explanation: