A cylindrical tank has a radius of 5.5 ft and an altitude of 16 ft. If a gallon of paint will cover 130ft^2 of surface, how much paint is needed to put two coats of paint on the entire surface of the tank?

Step-by-step explanation:

First we need to calculate the Total surface area of the cylindrical tank as shown;

TSA of the tank = 2πr² + 2πrh  

TSA of the tank = 2πr(r+ h)  where;

r is the radius of the tank

h is the height

Given

radius = 5.5ft

height = 16ft

Get the surface area;

TSA = 2π(5.5)(5.5+ 16)

TSA = 2π(5.5)(21.5)

TSA = 2π(118.25)

TSA = 2(3.14)(118.25)

TSA = 742.61ft²

If a gallon of paint will cover 130ft^2 of surface, then the total number of paint needed will be;

Total number of paint needed = 742.61/130

Total number of paint needed = 5.7

For one coat we will need 5.7gallons of paint

For two coats we will need 2 * 5.7gallons = 11.4

Hence approximately 11 gallons of paints will be needed for the two coats

inequality:

620-37.4p ≥ 450

the minimum amount of packages needed to be removed from the elevator is 5.

step-by-step explanation:

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)