Miya flips a coin and rolls a 6-sided number cube labled 1-6 and records tge outcome. About how many times is she likely to flip heads and roll a 3 out of 48 trials

4 times

Step-by-step explanation:

Sample space :

6 sided cube = (1, 2, 3, 4, 5, 6)

Coin = (H, T)

Probability = required outcome / Total possible outcomes

Probability of head (H) = P(H) = 1 /2 = 0.5

Probability of 3 = P(3) = 1 /6 = 0.166666

Probability of heads and 3 on a single try = p(H) * p(3) = 0.5 * 0.166666 = 0.083333

Hence, expected number of times this is likely to occur in 48 tries :

0.083333 * 48 = 4

correct answer is infinitely many solutions

step-by-step explanation:

2(2x + 3) = -4 + 2(2x + 5)

solving the above equation:

4x + 6 = -4 +4x +10

combining like terms

4x -4x = -4+10-6

0=0

since both sides are 0=0, we end up into true statement it means it has infinite many solutions.

so correct answer is infinitely many solutions

b

step-by-step explanation: