River collects old coins. He has four less than twice as many rare nickels as
he does rare quarters. I the face value
of the coins is $3.65, Which system of
equations can be used to find n, the
number of nickels, and ç, the number of
quarters that he has?
a) 25n +59 = 365
29-4=n
b) 5n +59 = 3.65
49 +2=n
c) 5n + 256 = 365
29-4=
d) 5n + 259 = 365
49-2=n
e) 25n +59 = 365
49-2=n

9514 1404 393

  c) 5n +25q = 365

     2q -4 = n

Step-by-step explanation:

The number of nickels (n) is 4 less than twice the number of quarters (q), so one of the equations is ...

  2q -4 = n

The face value is 365 cents, so another equation is ...

  5n +25q = 365

These equations seem to match choice C.

add the table and i will answer correctly

step-by-step explanation:

the answer is 9.8975

explanation:

when you multiply the "39.59" with the 25% it reduces it and shows its final discounted price. hope this !

step-by-step explanation: