A banks loan officer writes applications for credit the ratings are normally distributed with a mean of 200 and a standard deviation of 50 fine P 60 the score which separates the lower 60% from the top 40% round to 1 Decimal Pl.

212.7

Step-by-step explanation:

Calculation to Find P60 the score which separates the lower 60% from the top 40%

First step is to find z of 60% using the invNorm distribution

Hence,

z=0.6=0.2533

Now let Find P60 which is the score which separates the lower 60% from the top 40% using this formula

x<=>z

Where,

Standard deviation=50

Mean=200

z=0.2533

Let plug in the formula

x=0.2533*50+200

x=12.665+200

x=212.665

x=212.7(Approximately)

Therefore the score which separates the lower 60% from the top 40% is 212.7

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6

step-by-step explanation:

the shape,the size and the distance