Shaun estimated that the attendance at a college game was 1,200 people. The actual attendance was 1,158. What is the percent error of Shaun's estimate? (Round your answer to the nearest tenth)

The percentage error should be 3.6%

Given that,

Based on the above information, the calculation is as follows:

= 3.6%

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3.6%

Step-by-step explanation:

The formula for percent error is [ |va-ve/ve| * 100% ].

1200-1158/1158 * 100%

42/1158 * 100%

0.036 * 100%

3.6%

Best of Luck!

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1