Which of the following statements have the same result? Explain each step in solving each one. I. f(2) when f(x) = 3x + 4
II. f−1(4) when f(x) =3x-4/5
III. 3y − 6 = y + 10
You must solve each and show and explain each step. Then explain equivalency. Part 2 you must find the inverse equation.

None of the following statements have the same result.

Step-by-step explanation:

1) f(2) when f(x) = 3x + 4

We just have to put x=2

So, f(2) when f(x) = 3x + 4 is x=10

2) f⁻¹ (4)  when f(x) =3x-4/5

We need to find f⁻¹(x) first.

Put

Now solve for x

Add 4/5 on both sides

Now put  f⁻¹(x)  instead of x and replace y with x

Now finding f⁻¹(4)

f⁻¹ (4)  when f(x) =3x-4/5 is 24/15

3)

Solving:

Solving 3y − 6 = y + 10, we get y=8

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step-by-step explanation: