Given a term in an arithmetic sequence and the common difference, find the first five terms 1) a35 = -312, d = -10

I need the answer fast and if you can, please explain.

Step-by-step explanation:

we come with a1

a(n) = a1 +(n-1)d

a(35) = a1 +(35-1)-10=-312

So a1=-312+340= 28

first five terms:

a1= 28

a(2) = 28 +(2-1)-10=18

a(3) = 28 +(3-1)-10=8

a(4) = 28 +(4-1)-10=-2

a(5) = 28 +(5-1)-10=-12

hope it helps

yes yes yes yes yes yes yes yes yes

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb