What is the equation of the line that passes through the point (3, 4) and has a slope
of - 2/3?

y= - 2/3x+6

Step-by-step explanation:

Just plug in values into this equation (slope intercept form)

y=mx+b

3 is x value

4 is y value

m is the slope which is - 2/3

So after you plug in the values, solve for b ("b" is the y intercept):

4=-2/3(3)+b

4=-2+b

b=6

Then add in the b value into your equation and you will get y= - 2/3x+6

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!

none.

step-by-step explanation:

m

1

=

5

m1=5

b

=

−

1

b=-1

find the slope and y-intercept of the second equation.

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m

2

=

0

m2=0

b

=

−

6

b=-6

compare the slopes

m

m of the two equations.

m

1

=

5

,

m

2

=

0

m1=5,m2=0

compare the two slopes in the decimal form. if the slopes are equal, then the lines are parallel. if the slopes are not equal, then the lines are not parallel.

m

1

=

5

,

m

2

=

0

m1=5,m2=0