In right angled triangle abc ab=x cm bc=(x+7) and ac=17cm

2x^2+14x-240=0

Step-by-step explanation:

Remember Pythagoras's theorem?

a^2+b^2=c^2

So over here,

x^2+ (x+7)^2= 17^2 [ we need to now simplify (x+7)^2 --> (x+7) (x+7)  ]

x^2+ x^2+7x+7x+49= 289

2x^2+ 14x+49= 289

2x^2+14x+49=0 [ we need to make the right side zero coz thats

the rule for ]  

2x^2+14x-240=0

(idk, but i think the "show that  x^2) is wrong)

answer: i think it is (1,-2)