Triangle ABC is dilated to create triangle DEF on a coordinate grid. You are given that angle A is congruent to angle D. What other information is required to prove that the two triangles are similar? 1) Angle B is congruent to angle D.

2) Segments AB and DE are congruent.

3) Angle B is congruent to angle E.

4) Segment AC is congruent to segment DF, and segment BC is congruent to segment EF.

ITS NOT OPTION 4!!!

The correct option is;

Angle B is congruent to angle E

Step-by-step explanation:

The given parameters are;

Triangle ΔABC, is dilated into triangle ΔDEF

Therefore, ∠A, ∠B, and ∠C of triangle ΔABC corresponds with ∠D, ∠E, and ∠F, of triangle ΔDEF

Given that ∠A is congruent to ∠D, the other information required to prove that the two triangles are similar includes;

1) ∠B is congruent to ∠E which are corresponding angles

2) ∠C is congruent to ∠F which are also corresponding angles

Therefore, the correct option is angle B is congruent to angle E

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation:

geometry: triangles

solvers

lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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