Write in standard form of the equation of the line through the given points: through (2,2) and (-5,3)

y = -1/7 x + 16/7

Step-by-step explanation:

Write in standard form of the equation of the line through the given points: through (2,2) and (-5,3)

Given the point (2,2) and (-5,3). The standard form of an equation passing through the points is expressed as y = mx+c

m is the slope

c is the intercept

Get the slope

m = y2-y1/x2-x1

m = 3-2/-5-2

m = 1/-7

m = -1/7

Get the intercept. Substitute m = -1/7 and one of the point (2,2) into the expression y = mx+c

2 = -1/7(2) + c

2 = -2/7 + c

c = 2 + 2/7

c = (14+2)/7

c = 16/7

Substitute m = -1/7 and c = 16/7 into the expression y = mx+c

y = -1/7 x + 16/7

Hence the required equation is y = -1/7 x + 16/7

answer

see attachment

explanation

the given function is

this function has y-intercept at

-4 and a slope of 2.

note that, the graph has a positive slope.

the graph that represents this function is the straight line that moves upward from left to right.

the graph touches the y-axis at -4.

the correct choice is the graph shown in the attachment.

b

2

−

b

b

3

+

7

b

2

+

14

b

+

6

%

−

3

b

3

+

7

b

2

+

14

b

+

6

%

step-by-step explanation: