Find the value of functions f(x)=2x^2-3x+ given x=3x-5

Step-by-step explanation:

f(x) =2x^2 - 3x

f(3x -5) = 2(3x -5)^2 - 3(3x -5)

2 x 3x = 6x and 2 x -5 = -10

f(3x -5) = (6x -10)^2 - 3(3x -5)

-3 x 3x = -9x and 3 x -5 = -15

f(3x -5) = (6x -10)^2 - (-9x -15)

That's all I know ;-;- I forgot how to finish it

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!

nope.   happens to me as well.

-aparri