A function g(x) has x-intercepts at (3,0) and (6.0). Which could be g(x)? O g(x) = 2(x + 1)(x + 6)
O g(x) = (x-6)(2x - 1)
O g(x) = 2(x-2)(x-6)
O g(x) = (x + 6)(x + 2)

the answer is a if my teacher taught me correct

there would only be 50 odd numbers between 1 and 100 so therefor there would be 50 even so that would only be 50 odd numbers.

so the possibilities of the measurement of the side of the triangle are either it is longest side or not the longest side

when it is the longest side

s < 25 + 35s < 60

if it is not the longest side

35 < 25 + s10 < sso 10 < s < 60so the perimeter70 < p < 130