Ix times a larger number is equal to the sum of a smaller number and 18. The difference of twice the larger number and the smaller number is 6. Let x represent the smaller number and y represent the larger number. Which equations represent the situation? y = 6 x + 18. y = 2 x minus 6.
y = 6 (x + 18). Y = 2 (x minus 6).
y = one-sixth x + 3. y = one-half x + 6.
y = one-sixth x + 3. y = one-half x + 3.

6 times a larger number (so 6y) is equal (=) to the sum of a smaller number and 18 (x+18)

6y = x+18

Twice of larger number (2y) and the difference of smaller number (x) is equal to 6

2y - x = 6

solve for y. Divide both terms for 6.

6y/6 = 1/6x+3

y = 1/6x+3

second equation solve for y

move x to the right of equal

2y = x + 6

y = 1/2x + 3

C

Step-by-step explanation:

I took the test 2021

table 3 represents a direct variation function. : )