PLEASE HELP! 10 POINTS AND BRAINLIEST! Marcella is switching to a new storage locker.

1. What is the volume of the old locker? Show your work and include units.

2. What is the volume of the new locker? Show your work and include units.

3. Which locker is larger? By how much? Explain how.

THANK YOUUU

Step-by-step explanation:

ok so...

1 ) To find the volume of the old locker-->

volume of a cuboid=l*b*h

so, volume= 3*3*6

     volume=54ft^3

2) Now the old locker-->

volume of a cuboid=l*b*h (We apply the same formula)

lets multiply the height and the breadth first coz they're in mixed fractions->

2 1/2 * 5 1/2 [however we need to convert this into improper fraction first]

here are steps to convert mixed fractions to improper fractions-

Multiply the whole number part by the fraction's denominator.

Add that value to the numerator.

Then write the result on top of the denominator. (the denominator stays the same)

5/2*11/2= 55/4

now we can multiply this value to the length (coz till now we only did b*h)

55/4*4/1  [remember that there is always an imaginary 1 existing under no.s]

v=220/4   we can convert this into a whole no. by divison [just divide]

so the volume= 55ft^3

3) We can easily compare which no. is bigger...

55 or 54...well ys the ans is 55 so the old locker has more storage

space.    

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)