Whats the sum of 4 consecutive odd integers is 4 less than 100. what is the second largest integer?

Let, the numbers = x,(x+2),(x+4),(x+6)

x+x+2+x+4+x+6 = 100-4 = 96

4x+12=96

4x = 84

x = 84/4 = 21

Second largest number, (x+2) = 21+2 = 23

So, your answer is 23

y=1/4x-4

step-by-step explanation:

6.5

step-by-step explanation:

you said it was in the question

~courtney