The price p (in dollars) and the quantity x sold of a new smartphone obey the demand equation p=-1/10x +1000 what quantity x of the new smartphone maximizes the revenue

answer: 457.14

step-by-step explanation:

205 - 45 = 160

160 / .35 = 457.142857

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

ending amount = beginning amount / (2^n)

where "n" = number of half-lives (or elapsed time / half-life)

ending amount = 50 mg / (2 ^10 / 5.3)

ending amount = 50 mg / (2 ^ 1.8867924528)

ending amount = 50 m / 3.6981210597

ending amount = 13.5203794557 mg

or about 13.5 mg remain

source:  

1/4 is the asnwer cuz 5/20 is the faction