How will the solution of the system y > 2x + 2 and y< B 2x + } change if the inequality sign on both inequalities is reversed to y < 2x+ and y2x+12

2.83941151 would be the answer you're looking for! : )

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

answer: 12x^2+6x

step-by-step explanation:

6x does not equal 24x. hope it works!

i don't see any steps below, sweetheart