Let the random variable X represent the weight of male black bears before they begin hibernation. Research has shown that X can be modeled by a Normal distribution with a mean of 250 pounds and a standard deviation of 50 pounds. What is the probability that a randomly selected male black bear will weigh more than 325 pounds before beginning hibernation? a
0.0668
b
0.7486
c
0.2514
d
0.8531
e
0.9332

well you see to solve this equation you must take the classes to aquire such intelegence to understand the basiscs of PEMDAS so then you can start on the more advanced stuff such as this

15%

step-by-step explanation:

use the table and count the number of guesses that has two correct answers.

the following are two correct answers

10010, 01100, 11000

a total of 3 numbers having 2 correct guesses out of 20 questions.

probability of getting 2 correct guesses = the number of questions getting 2 correct answers / total number of questions.

= 3/20

to convert it into percent multiply by 100, we get

= 3/20 * 100

= 15%

the answer is 15%

you.