heights of adults women have a mean of 63.6 in and a standard deviation of 2.5 indies chebyshevs theorem say about the percentage of women with heights between 58.6 and 68.6in

Chebyshev's Theorem (Tchebysheff's Theorem) suggests that this percentage would be greater than .

Step-by-step explanation:

Let be a random variable with a mean of and a (finite) variance of . By Chebyshev's Theorem, for any constant where :

.

In this question, let denote height (in inches.) Accordingly, whereas .

Note, that the interval of interest is centered at . Besides, the difference between and either endpoints of this interval is equal to , which is the same as .

Rewrite the interval as .

For the height of one such individual, is equivalent to . With whereas , that expression is equivalent to .

The percentage of individuals with a height in the interval would be equal to the probability .

Compare this expression to Chebyshev's Theorem. Notice that . Therefore:

.

In other words, at least of the heights would be between inches and inches.

i used to know how to do this in 7th but i forget easily

step-by-step explanation:

step-by-step explanation: