Two people are pulling on a rope in order to get a 2250-kg car out of a mud puddle. One person pulls with a force of 600 N and the other pulls with a force of 800 N. There is a resistive frictional force of 1200 N. Use the acceleration found in the previous question to determine the distance they would pull the vehicle in 25s (answer with 2 digits, include properly abbreviated units) *

Assuming both people are pulling in the same direction, the net force on the car is, according to Newton's second law,

600 N + 800 N - 1200 N = (2250 kg) a

Solve for the acceleration a :

200 N = (2250 kg) a

a = (200 N) / (2250 kg)

a ≈ 0.0889 m/s/s

Step-by-step explanation: I hope this helps!

-4

step-by-step explanation:

(-4+8)=-(4-8)=-8+4=-4

step-by-step explanation:

we are given a graph for system of inequalities.

in order to write the system of inequalities for the given graph, we need to find the inequality for each of the line separately.

let us find the slope of dotted line first.

taking two coordinates on the graph.

let us say (0,0) and (3,1).

let us find the slope of the line now.

slope of the dotted line would be =.

y-intercept of dotted line is y=0 only.

plugging slope m= and b=0 in slope-intercept form y=mx+b, we get

.

the line is shaded up of that dotted line.

therefore, for shading up we would take greater than inequality symbol > .

and because it's a dotted line we would take only > symbol in place of = sign in above equation of line.

therefore, inequality for dotted line would be

let us take two points (3,1) and (0,4) on the solid line.

slope of the solid line would be =.

for the solid line we have y-intercept b= 4.

plugging slope m= -1 and b=4 in slope-intercept form y=mx+b, we get

y = -1x + 4.

the line is shaded down of that solid line.

therefore, for shading down we would take less than inequality symbol < .

and because it's a solid line we would take ≤ symbol in place of = sign in above equation of line.

therefore, inequality for solid line would be