An online furniture store sells chairs for $150 each and tables for $550 each. The store must sell at least $8500 worth of chairs and tables each day. Write an inequality
that could represent the possible values for the number of tables sold, t, and the
number of chairs sold, c, that would satisfy the constraint.

550t + 150c ≥ 8500

Step-by-step explanation: the store makes 550 for each table sold, so for t tables, the store will make 550t dollars. The store makes 150 for each chair sold, so for c chairs, the store will make 150c dollars. Therefore, the total revenue 550t + 150c must be greater than or equal to 8500

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

ur mom

step-by-step explanation: