A fair six-sided die is tossed 10 times, with results written in a string. The fi rst trial gave a string with only 5s and 6s. What is the probability of the 10 tosses giving a string that has only numbers greater than 4?

1/3 or 0.333333

Step-by-step explanation:

The question talks about a die that was tossed once and we are now asked to find the probability that it is a figure greater than 4

---A die has 6 faces with the numbers 1,2,3,4,5 and 6 one on each of

the six faces. Considering an unbiased die the probability of any of the faces to appear in a single roll is 1/6.

So, P(1)=P(2)=P(3)=P(4)=P(5)=P(6)=1/6

Now that numbers greater than 4 are 5 and 6

So it can be P(5) or P(6)= P(5)+P(6)=2/6 = 1/3 or 0.33333

Answer 1/3 or 0.33333

Hope this helps :)

-Danny

that is the sum

step-by-step explanation:

there are no other answers without knowing the variables values

70

step-by-step explanation: