Help again! algebra 1

maybe c?

Step-by-step explanation:

from eqn. 1

3x + 2y = 23

2y = 23 - 3x

y = 23/2 - 3/2x

sub into eqn. 2

1/2x - 4 = 23/2 - 3/2x

1/2x + 3/2x = 23/2 + 4/1

2x = 23/2 + 8/2

2x = 31/2

x = 31/4

sub into eqn. 1

31/4 + 2y = 23

2y = 23 - 31/4

2y = 92/4 - 31/4

2y = 61/4

y = 61/8 or 7 5/8  

ummm i got something wrong but try c?

C . 31/4,-1/8

Step-by-step explanation:

1. sub the given value of y

into 3x + 2 (1/2x -4) 23

2. slove for x = 31/4

3.sub the given value of x into 1/2x - 4 =y

4. solve the equation for y

5. y = -1/8

6. ordered pair to (x,y) = 31/4,1,8

step-by-step explanation:

because 1/3 is a fraction. we can tell because there is a divisor symbol between the 1 and the 3. if we were to add 2 fractions together, we would add the numerators, which is the number on top, but not the denominators, which is the number on the bottom

1/3+1/3=2/3

hope this !

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8