Please really need help

Which of the following equations is of the parabola whose vertex is at (2, 3), axis of symmetry parallel to the y-axis and p = 4? a.)y-3 = 1/16 (x-2)^2 b.)y+3 = -1/16 (x+2)^2 c.)x-2 = 1/16 (y-3)^2

Atransformation t : (x,y) (x-5,y +3) the image of a(2,-1) is

Find the vertex for the parabola given by the function ƒ(x) = −3x2 − 6x.