Amaal converted the following conic equation from general form to standard form. 4x2 + 4y2 – 16x + 24y – 12 = 0

4x2 – 16x + 4y2 + 24y = 12

4(x2 – 4x) + 4(y2 + 6y) = 12

4(x2 – 4x + 4) + 4(y2 + 6y + 9) = 12 + 4 + 9

4(x – 2)2 + 4(y + 3)2 = 25

Jamaal identifies the center of the circle as

(2, –3) and the radius as r = Five-halves.