Lavasha and Keisha travel separately to their grandmother’s house, 114 miles away. Keisha leaves from the same place 30 minutes after Lavasha. If Lavasha is travelling at 40 mph and Keisha travels at 55 mph, how many minutes will it take Keisha to catch up to Lavasha?

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

536

step-by-step explanation: