In simplest radical form, what are the solutions to the quadratic equation 0 =3x4x + 5? Quadratic formula: x= btyb- 4ac

Given:

The quadratic equation is

To find:

The simplest radical form of the solution.

Solution:

Quadratic formula:

If a quadratic equation is , then

We have,

Here, a=-3, b=-4 and c=5. Putting these values in the quadratic formula, we get

Taking 2 common, we get

Therefore, the correct option is A.

step-by-step explanation:

i found the koficent of the linear function and i foun c acordind to the strict formula y=kx+c and then i took 2 as an x and replacet it on the formula i found and then foun the y

2x + 8

step-by-step explanation: