Onsider the line y=-5+6. find the equation of the line perpendicular to this line and passes through the point (-2,-3)
find the equation of the is parallel to this line and passes through the point (-2,-3)

The equation of the line perpendicular to the given line is

.

The equation of the line perpendicular to the given line is

.

Step-by-step explanation:

The given line is y=-5x+6

The slope of the given line,

Let be the slope of the line perpendicular to y=-5x+6,

where is constant.

As multiplication of slopes of two perpendicular lines equal to -1, so

So, the equation of the line perpendicular to the given line is

which passes through the point (-2,-3), so

Hence, the equation of the line perpendicular to the given line is

.

Now, let be the equation of the parallel line to y=-5x+6.

As the slopes of two parallel lines are the same, so .

So, the equation of the parallel line becomes

which passes through the point (-2,-3), so

Hence, the equation of the line perpendicular to the given line is

.

i think is g(1)=-1.

hope that i can

if e is the midpoint of bd, then bd is 14.

step-by-step explanation: