Consider a population with 3 observations: 6, 10 and 12. You use simple random sampling without replacement to select a sample of 2 observations. What is the probability that the sample mean is larger than 8?

Step-by-step explanation:

Given that:

The number of observations is:

6, 10, 12

If we are to use a simple  random sampling without replacement, then we will have:

(6,10)  (6,12)  (10,12)

Here;

the sample size n = 2

The population size N = 3

For (6,10) ; The sample mean =

=

= 8

For (6,12) ; The sample mean =

=

= 9

For (10, 12) ; The sample mean =

=

= 11

The probability distribution of sample mean(x) is:

X           8           9          11

P(X=x)                        

Thus, the probability that the sample mean  is larger than 8 is:

P(X> 8) = P(X = 9) + P(X + 11)

P(X> 8) =

P(X > 8) =

P(X> 8) =

let y equal to

the total fare and x is the mile of taxi ride. so the equation is

y = 0.55x + 1.75

since susie has

$10 to spend for a taxi cab, so he can have

10 = 0.55x +

1.75

x = 15 miles of

taxi ride

so the system of

inequality is

10 < 0.55x +

1.75

x > 2