There are four activities on the critical path. Coincidentally, their standard deviations are all equal to 4. The standard deviation of the critical path is therefore equal to:

the standard deviation of the critical path is 8

Step-by-step explanation:

The computation of the standard deviation of the critical path is shown below:

As we know that

Variance = Standard deviation^2

Now the variance of the critical path is

= Variance 1 + variance 2 + variance 3 + variance 4

= 4^2 + 4^2 + 4^2 + 4^2

= 64

Now the standard deviation would be

= √64

= 8

hence, the standard deviation of the critical path is 8

i used to know how to do this in 7th but i forget easily

step-by-step explanation:

the answer is c

step-by-step explanation: