An object dropped from rest from the top of a tall building on Planet X falls a distance feet in the first t seconds. Find the average rate of change of distance with respect to time as t changes from to . This rate is known as the average velocity, or speed. The average velocity as t changes from to seconds is:

Complete Question:

An object dropped from rest from the top of a tall building on Planet X falls a distance d(t)=13t^2 feet in the first t seconds. Find the average rate of change of distance with respect to time as t changes from t1=2 to t2=10. This rate is known as the average velocity, or speed.

The average velocity as t changes from 2 to 10 seconds is _______ feet/sec?

Step-by-step explanation:

Given

Time Interval: (a,b)

Required

Determine the average rate of change (v)

This is calculated as thus:

Substitute values for b and a

Calculate d(10): Substitute 10 for t

Calculate d(2): Substitute 2 for t

The equation becomes

Hence, the average rate of change is 156ft/s

351°f

step-by-step explanation: