A bag has six balls labeled A, B, C, D, E, and F. One ball will be randomly picked, and its letter will be recorded as the outcome.
Give the sample space describing all possible outcomes.
Then give all of the outcomes for the event of choosing the letter A or C.
If there is more than one element in the set, separate them with commas.
Sample space: {I
DO.
Event of choosing the letter A or C : {0}
Х
?

Uneed to add them up 27+18+23=68

First subtract 10 from both side
y^2+6y-16=0
(y+8)(y-2)=0
-8 and 2

The answer is 270 cars.you can do this by making a proportional relationship. for instance, 200 is the whole we are using, so on a “number line” 200 would be over 100%. now, since he sells 35% more, add 35% to 100% to get 135% on the other side of the “number line” on the bottom half, leaving the top half empty.cross multiply 200 by 135 then divide by 100 to get your answer. i hope this , if it did, , if you don’t mind, giving me brainiest! 200/100% } 200 • 135 /100 ? /135%