The volume of air contained in the lungs of a certain athlete is modeled by the equation =338sin(61)+744, where is time in minutes, and is volume in cubic centimeters. What is the maximum possible volume of air in the athlete's lungs?
Maximum volume=
cubic centimeters

What is the minimum possible volume of air in the athlete's lungs?
Minimum volume=
cubic centimeters

How many breaths does the athlete take per minute?
breaths per minute

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p

answer: options

step-by-step explanation: