Find the value of X for which log X, log (X+2) and log (X+16) are three consecutive terms of an arithmetic series.

x=-2

Step-by-step explanation:

log x, log (x+2) , log (x+16) are in A.P.

2log (x+2)=log (x+2) +log (x+16)

log (x+2)²=log [(x+2)(x+16)]

(x+2)²=(x+2)(x+16)

x²+4x+4=x²+2x+16x+32

4x-18x=32-4

-14x=28

x=28/(-14)=-2

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.

it shoild be o

step-by-step explanation: