Which statement correctly compares the function shown on this graph with the function y = 6x - 1? A. the function shown on the graph has a smaller rate of change and a lower starting point

B. the function shown on the graph has a greater rate of change and a higher starting point

C. the function shown on the graph has smaller rate of change, but a high starting point

D. the function shown on the graph has a greater rate of change and a lower starting point

we conclude that the function shown in the graph has a smaller rate of change and a lower starting point.

Therefore, option (A) is true.

Step-by-step explanation:

FUNCTION

Given the function

y = 6x - 1

Comparing with the slope-intercept form of the graph

y = mx+b

where m is the slope and b is the y-intercept

Thus,

The slope of the function  = rate of change = 6

The starting point of the function can be obtained by setting x = 0 and solve for y

i.e

at x = 0, y = 6x-1 = 6(1)-1 = 5

Thus,

The starting point of the function is (0, 5)

                 

LINE GRAPH

Now, consider the line graph

Taking two points to find the slope

(0, -6)(2, 4)

Thus,

The slope of the line graph  =  rate of change = 5

From the graph, it is clear that at x=0, the value of y=6

Thus,

The starting point of the graph is (0, -6)

Thus,

FOR FUNCTION

The slope of the function  = rate of change = 6

The starting point of the function is (0, 5)

FOR LINE GRAPH

The slope of the line graph  = rate of change = 5

The starting point of the graph is (0, -6)

Conclusion

Hence, we conclude that the function shown in the graph has a smaller rate of change and a lower starting point.

Therefore, option (A) is true.

     

Abit confused about what you mean, but i think you might be referring to slope intercept form: y = mx + bin that case b, or the y intercept is already given.(0,-1)find the slope by using the formulay2 - y1/x2 - x1the final slope will be 4/2, equivalent to 2.now your equation should look like thisy = 4/2x -1sorry if this didn’t you out!

First subtract 10 from both side
y^2+6y-16=0
(y+8)(y-2)=0
-8 and 2