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Mathematics, 13.12.2020 23:50 love0000

2sin 3x * cos x - 2cos 3x * sin x = - sqrt(2) in the interval [0,2pi)


2sin 3x * cos x - 2cos 3x * sin x = - sqrt(2) in the interval [0,2pi)

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2sin 3x * cos x - 2cos 3x * sin x = - sqrt(2) in the interval [0,2pi)
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