Determine the sum of the exterior angles in a convex 50-gon. (G.10)(1 point)

The sum of the exterior angles in a convex 50-gon polygon is 360° ⇒ A

Step-by-step explanation:

In the question

∵ The polygon has 50 sides

→ By using the 3rd rule above

∵ The sum of the exterior angles of any polygon (n-gon) is 360°

∴ The sum of the exterior angles in a convex 50-gon polygon is 360°

9.55 degrees.

step-by-step explanation:

the given angle is

1 cycle is equal to 2π radians. so 4π will be equal to two cycles.

5.166667π-4π = 1.166667π

hence, this angle goes a little more than negative x axis.

1.166667π-π= 0.166667π

hence, the reference angle is 0.166667π radians.

1 radian = 57.2958 degrees

now, in degrees, this should be equals to 9.55 degrees.

b.my answer is b.

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