Solve using substitution and show your work:
-3x-3y=3
y=-5x-17

Step-by-step explanation:

Isolate any variable, x or y, but since y has already been isolated, use y to solve for x.

Substitute y into the first equation -3x-3y=3

This equals -3x - 3 (-5x - 17) = 3

Distribute to get -3x + 15x + 51  = 3

Then bring like terms together. -3x + 15x = 3 - 51

12x = -48

Solve for x

x = -4

Substitute -4 for x in the equation: y = -5x - 17

y = − 5x − 17

y = (−5) (−4) − 17

y = 20 - 17

y = 3 ( Simplify both sides of the equation)

x = − 4 and y = 3

the answer is d

step-by-step explanation:

y+3=-4(x-2)

y+3=-4x+8

  -3         -3  

y=-4x+5

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐